Thanks!

1. What does the given "Exposure distribution" represent?:
   1. it's not G(x) since it's not an increasing function (and also G(x) is the objective of this question :) )
   2. it's not G'(x) otherwise 1/G'(0) would be equal to the mean and 1/80% is not the mean (normalized or not normalized)
   3. it's also not F(x) or f(x), since the examiner's report says we should have transformed the "exposure distribution" into a distribution of losses
2. in the sample answer #2, the accepted definition of G(x) is E[x;1]/E[x]. since x is the normalized loss, this implies that E[x;1] = E[x], and therefore the accepted definition of G(x) yields G(x) = 1. How does this tie to the definition of G(d) on page 101, where G(d) = E[min(x;d)]/E[x].

In my opinion this is a key problem to understand the basics of this paper, but maybe it's notation, or a poorly written CAS question, or a code-18... but there is a lot that could be clarified here.

Thanks for any clarification you can provide